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186 questions
Physics/Paper 2/Dynamics
CAIEAS Level9702-as · Paper 2

Dynamics

186 questions· page 1 of 19

Q42025 May/Jun·P233 partsEasy
(a)

State the principle of conservation of momentum.

(b)(i)

Calculate:

velocity vv

vv = ______ m s1\text{m s}^{-1}

(b)(ii)

the percentage of the total initial kinetic energy of the two objects that is transferred to other forms of energy during the collision.

percentage = ______ %\%

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Q22025 May/Jun·P246 partsEasy
(a)

Define momentum.

(b)

Calculate the change in momentum of the object from time t=0t = 0 to t=12 st = 12\text{ s}.

change in momentum = ______ kg m s1\text{kg m s}^{-1}

(c)

Calculate the magnitude of the resultant force acting on the object.

force = ______ N\text{N}

(d)

Describe the variation of the speed of the object from time t=0t = 0 to t=8.0 st = 8.0\text{ s}.

(e)

By reference to Fig. 2.1, explain why the resultant force acting on the object during the first 8.0 s8.0\text{ s} of its motion cannot be due to air resistance.

(f)

At time t=0t = 0 the displacement dd of the object is zero.

On Fig. 2.2, sketch the variation of dd with time tt from t=0t = 0 to t=12 st = 12\text{ s}.

Numerical values of dd are not required.

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Q32024 May/Jun·P213 partsEasy
(a)

State the principle of conservation of momentum.

(b)

An object of mass 2m2m is travelling at a speed of 5.0 m s15.0\text{ m s}^{-1} in a straight line. It collides with an object of mass 3m3m which is initially stationary, as shown in Fig. 3.1.

After the collision, the object of mass 2m2m moves with velocity vv at an angle of 3030^\circ to its original direction of motion.

The object of mass 3m3m moves with velocity ww also at an angle of 3030^\circ, as shown in Fig. 3.2.

By considering the conservation of momentum in two dimensions, calculate the magnitudes of vv and ww.

vv = ______ m s1\text{m s}^{-1}
ww = ______ m s1\text{m s}^{-1}

(c)

An object of mass 4.2 kg4.2\text{ kg} is travelling in a straight line at a speed of 6.0 m s16.0\text{ m s}^{-1}. The object is brought to rest in a distance of 0.050 m0.050\text{ m} by a constant force.

Calculate the magnitude of this force.

force\text{force} = ______ N\text{N}

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Q22024 Oct/Nov·P216 partsEasy
(a)

Define linear momentum.

(b)(i)

Calculate the maximum speed reached by the car.

maximum speed = ______ m s1\text{m s}^{-1}

(b)(ii)

Calculate the maximum kinetic energy of the car.

maximum kinetic energy = ______ J\text{J}

(b)(iii)

Show that the acceleration of the car at time t=4.0 st = 4.0\text{ s} is 5.0 m s25.0\text{ m s}^{-2}.

(b)(iv)

Determine the distance travelled by the car between times t=0t = 0 and t=12.0 st = 12.0\text{ s}.

distance = ______ m\text{m}

(c)

On Fig. 2.2, sketch the variation with time tt of the acceleration aa of the car in (b) from t=0t = 0 to t=12.0 st = 12.0\text{ s}.

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Q22024 Oct/Nov·P235 partsEasy
(a)

State the principle of conservation of momentum.

(b)(i)

Show that the speed vv of ball Y after the collision is 8.0 m s18.0\ \text{m s}^{-1}.

(b)(ii)

Calculate the change in the total kinetic energy ΔEK\Delta E_K of the balls due to the collision.

ΔEK\Delta E_K = ______ J\text{J}

(c)(i)

Determine the magnitude and direction of the force exerted on ball X by ball Y during the collision.

magnitude = ______ N\text{N}
direction ______

(c)(ii)

Compare the magnitude and direction of the force exerted on ball Y by ball X during the collision with the answers in (c)(i). No further calculations are required.

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Q42023 Feb/Mar·P223 partsMedium-Easy
(a)

Block X has an initial kinetic energy of 0.30 J0.30\text{ J}.

Calculate the mass of block X.

mass = ______ kg\text{kg}

(b)

Determine the magnitude of the momentum of block Y after the collision.

momentum = ______ kg m s1\text{kg m s}^{-1}

(c)

Block X exerts an average force of 7.7 N7.7\text{ N} on block Y during the collision.

Calculate the time that the blocks are in contact with each other.

time = ______ s\text{s}

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Q32023 May/Jun·P214 partsEasy
(a)

State Newton’s second law of motion.

(b)(i)

the resultant force on the block

resultant force = ______ N\text{N}

(b)(ii)

the force XX.

XX = ______ N\text{N}

(c)

On Fig. 3.3, sketch a graph to show the variation of force XX with time tt from t=0t = 0 to $t = 6.0\ \text{s}.

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Q32023 May/Jun·P225 partsEasy
(a)(i)

Define force.

(a)(ii)

Determine the change in momentum of the block from time t=0t = 0 to time t=3.0 st = 3.0\ \text{s}.

change in momentum = ______ kg m s1\text{kg m s}^{-1}

(b)(i)

Describe and explain the motion of the block between time t=3.0 st = 3.0\ \text{s} and time t=6.0 st = 6.0\ \text{s}.

(b)(ii)

Force XX produces a total power of 2.0 W2.0\ \text{W} when moving the block between time t=3.0 st = 3.0\ \text{s} and time t=6.0 st = 6.0\ \text{s}.

Calculate the distance moved by the block during this time interval.

distance = ______ m\text{m}

(c)

The block is at rest at time t=0t = 0.

On Fig. 3.3, sketch a graph to show the variation of the momentum of the block with time tt from t=0t = 0 to t=6.0 st = 6.0\ \text{s}.
Numerical values of momentum are not required.

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Q42023 Oct/Nov·P224 partsMedium-Easy
(a)(i)

Calculate the component of the final momentum of ball Y in the direction perpendicular to line PQ.

component of momentum = ______ Ns\text{Ns}

(a)(ii)

By considering the component of the final momentum of each ball in the direction perpendicular to line PQ, calculate mZm_Z.

mZm_Z = ______ kg\text{kg}

(a)(iii)

During the collision, the average force exerted on Y by Z is FYF_Y and the average force exerted on Z by Y is FZF_Z.

Compare the magnitudes and directions of FYF_Y and FZF_Z. Numerical values are not required.

magnitudes: .......................................................................................................................

directions: ..........................................................................................................................

(b)

Two blocks, A and B, move directly towards each other along a horizontal frictionless surface, as shown in the view from above in Fig. 4.3.

The blocks collide perfectly elastically. Before the collision, block A has a speed of 4 m s14\ \text{m s}^{-1} and block B has a speed of 6 m s16\ \text{m s}^{-1}. After the collision, block B moves back along its original path with a speed of 2 m s12\ \text{m s}^{-1}.

Calculate the speed of block A after the collision.

speed = ______ m s1\text{m s}^{-1}

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Q42022 May/Jun·P223 partsEasy
(a)

State the principle of conservation of momentum.

(b)(i)

By considering the components of the momenta along the line AB, calculate θ\theta.

θ\theta = ______ ^\circ

(b)(ii)

By calculation of kinetic energies, state and explain whether the collision of the balls is inelastic or perfectly elastic.

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