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147 questions
Chemistry/Paper 4/Chemical Energetics
CAIEA-Level9701-a · Paper 4

Chemical Energetics

147 questions· page 1 of 15

Q42025 May/Jun·P415 partsEasy
(a)(i)

Define enthalpy change of hydration.

(a)(ii)

Explain the relative magnitudes of the enthalpy changes of hydration of K+\text{K}^+ and Ca2+\text{Ca}^{2+}.

(a)(iii)

Define lattice energy.

(a)(iv)

The lattice energy, ΔHlatt\Delta H_{\text{latt}}, of calcium fluoride, CaF2\text{CaF}_2, is 2602 kJ mol1-2602 \text{ kJ mol}^{-1}.

Calculate the enthalpy change of solution, ΔHsol\Delta H_{\text{sol}}, in kJ mol1\text{kJ mol}^{-1}, of CaF2\text{CaF}_2.

(b)

The formation of CaF2\text{CaF}_2 at 298 K is shown.

Ca(s)+F2(g)CaF2(s)ΔH=1214 kJ mol1, ΔG=1162 kJ mol1\text{Ca(s)} + \text{F}_2\text{(g)} \rightarrow \text{CaF}_2\text{(s)} \quad \Delta H^\ominus = -1214 \text{ kJ mol}^{-1}, \ \Delta G^\ominus = -1162 \text{ kJ mol}^{-1}

Calculate the entropy change, ΔS\Delta S^\ominus, in J K1 mol1\text{J K}^{-1} \text{ mol}^{-1}, for this reaction.

Similar questions
Q32025 May/Jun·P425 partsEasy
(a)

Define entropy.

(b)(i)

Identify the process occurring at each of the temperatures T1T_1 and T2T_2.

T1T_1 .................................................. T2T_2 ..................................................

(b)(ii)

Explain why the entropy change, ΔS\Delta S, at T2T_2 is bigger than the entropy change at T1T_1.

(c)

The equation for the reduction of iron(III) oxide by carbon monoxide at 450 C450\text{ }^\circ\text{C} is shown.

Fe2O3(s)+3CO(g)2Fe(s)+3CO2(g)ΔG=36.2 kJ mol1\text{Fe}_2\text{O}_3(\text{s}) + 3\text{CO}(\text{g}) \rightarrow 2\text{Fe}(\text{s}) + 3\text{CO}_2(\text{g}) \quad \Delta G^\ominus = -36.2\text{ kJ mol}^{-1}

Table 3.1 shows the enthalpy of formation, ΔHf\Delta H_f^\ominus, and the entropy, SS^\ominus, for some substances.

Table 3.1

Fe2O3(s)\text{Fe}_2\text{O}_3(\text{s})CO(g)\text{CO}(\text{g})Fe(s)\text{Fe}(\text{s})CO2(g)\text{CO}_2(\text{g})
ΔHf/kJ mol1\Delta H_f^\ominus / \text{kJ mol}^{-1}824.2-824.2110.5-110.50.00.0393.5-393.5
S/J K1 mol1S^\ominus / \text{J K}^{-1}\text{ mol}^{-1}87.487.4to be calculated27.327.3213.8213.8

Use the data in Table 3.1 to calculate the entropy, SS^\ominus, of carbon monoxide at 450 C450\text{ }^\circ\text{C}.

Show your working.

(d)

Iron(II) oxide can also be reduced to iron by carbon monoxide, as shown.

FeO(s)+CO(g)Fe(s)+CO2(g)ΔH=11.1 kJ mol1,ΔS=15.2 J K1 mol1\text{FeO}(\text{s}) + \text{CO}(\text{g}) \rightarrow \text{Fe}(\text{s}) + \text{CO}_2(\text{g}) \quad \Delta H^\ominus = -11.1\text{ kJ mol}^{-1}, \quad \Delta S^\ominus = -15.2\text{ J K}^{-1}\text{ mol}^{-1}

State the effect of increasing temperature on the feasibility of this reaction.

Explain your answer.

Similar questions
Q42025 May/Jun·P435 partsEasy
(a)(i)

Define enthalpy change of hydration.

(a)(ii)

Explain the relative magnitudes of the enthalpy changes of hydration of K+\text{K}^+ and Ca2+\text{Ca}^{2+}.

(a)(iii)

Define lattice energy.

(a)(iv)

The lattice energy, ΔHlatt\Delta H_{\text{latt}}, of calcium fluoride, CaF2\text{CaF}_2, is 2602 kJ mol1-2602\text{ kJ mol}^{-1}.

Calculate the enthalpy change of solution, ΔHsol\Delta H_{\text{sol}}, in kJ mol1\text{kJ mol}^{-1}, of CaF2\text{CaF}_2.

ΔHsol\Delta H_{\text{sol}} of CaF2\text{CaF}_2 = .............................. kJ mol1\text{kJ mol}^{-1}

(b)

The formation of CaF2\text{CaF}_2 at 298 K is shown.

Ca(s)+F2(g)CaF2(s)ΔH=1214 kJ mol1, ΔG=1162 kJ mol1\text{Ca(s)} + \text{F}_2\text{(g)} \rightarrow \text{CaF}_2\text{(s)} \quad \Delta H^\ominus = -1214\text{ kJ mol}^{-1}, \ \Delta G^\ominus = -1162\text{ kJ mol}^{-1}

Calculate the entropy change, ΔS\Delta S^\ominus, in J K1 mol1\text{J K}^{-1}\text{ mol}^{-1}, for this reaction.

ΔS\Delta S^\ominus = .............................. J K1 mol1\text{J K}^{-1}\text{ mol}^{-1}

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Q82025 May/Jun·P445 partsEasy
(a)(i)

Define lattice energy, ΔHlatt\Delta H_\text{latt}.

(a)(ii)

Define enthalpy change of solution, ΔHsol\Delta H_\text{sol}.

(b)

The enthalpy change of hydration can be represented by ΔHhyd\Delta H_\text{hyd}.

Write the mathematical expression for the ΔHsol\Delta H_\text{sol} of NaCl\text{NaCl} in terms of ΔHlatt(NaCl)\Delta H_\text{latt}(\text{NaCl}), ΔHhyd(Na+)\Delta H_\text{hyd}(\text{Na}^+) and ΔHhyd(Cl)\Delta H_\text{hyd}(\text{Cl}^-).

ΔHsol(NaCl)=\Delta H_\text{sol}(\text{NaCl}) = \rule{8cm}{0.5pt}
(c)

Complete the Born–Haber cycle in Fig. 8.1 for the ionic solid NaCl\text{NaCl}.

Include state symbols of relevant species.

(d)

Predict which of the ions, Cl\text{Cl}^- or NO3\text{NO}_3^-, has the more negative enthalpy change of hydration.

Explain your answer.

Similar questions
Q42025 Oct/Nov·P424 partsEasy
(a)

Define enthalpy change of atomisation, ΔHat\Delta H_{at}.

(b)

Define first electron affinity, EA.

(c)

Explain why the first electron affinity of chlorine is more exothermic than the first electron affinity of iodine.

(d)

The enthalpy change for the reaction Cl2(g)+2e2Cl(g)\text{Cl}_2\text{(g)} + 2\text{e}^- \rightarrow 2\text{Cl}^-\text{(g)} is 486 kJ mol1-486 \text{ kJ mol}^{-1}.

The first electron affinity of chlorine is 364 kJ mol1-364 \text{ kJ mol}^{-1}.

Calculate the enthalpy change of atomisation of chlorine.

ΔHat\Delta H_{at} of chlorine = .............................. kJ mol1\text{kJ mol}^{-1}

Similar questions
Q32025 Oct/Nov·P445 partsEasy
(a)

Define the term entropy.

(b)(i)

Place one tick (\checkmark) in each row of Table 3.1 to show the sign of the entropy change, ΔS\Delta S, for each process.

Table 3.1

processΔS\Delta S is negativeΔS\Delta S is positive
steam condensing into water
solid KCl\text{KCl} dissolving in water
(b)(ii)

Chlorine trifluoride, ClF3\text{ClF}_3, decomposes on heating into its elements, as shown.

reaction 12ClF3(g)Cl2(g)+3F2(g)\text{reaction 1} \quad 2\text{ClF}_3(\text{g}) \rightarrow \text{Cl}_2(\text{g}) + 3\text{F}_2(\text{g})

Standard entropies are shown in Table 3.2.

Table 3.2

substanceClF3(g)\text{ClF}_3(\text{g})Cl2(g)\text{Cl}_2(\text{g})F2(g)\text{F}_2(\text{g})
S/J K1mol1S^\ominus / \text{J K}^{-1} \text{mol}^{-1}+281.6+281.6+223.1+223.1+203.0+203.0

Calculate the standard entropy change, ΔS\Delta S^\ominus, in J K1mol1\text{J K}^{-1} \text{mol}^{-1}, for reaction 1.

(c)(i)

Predict the sign of the entropy change, ΔS\Delta S, for reaction 2.

Explain your answer.

(c)(ii)

The Gibbs equation is shown.

ΔG=ΔHTΔS\Delta G^\ominus = \Delta H^\ominus - T\Delta S^\ominus

Fig. 3.1 shows values of the Gibbs free energy change, ΔG\Delta G^\ominus, in kJ mol1\text{kJ mol}^{-1}, at different temperatures, TT, in K\text{K}, for reaction 2.

Assume ΔH\Delta H^\ominus and ΔS\Delta S^\ominus values for this reaction remain constant over this temperature range.

Use the gradient and intercept on the yy-axis in Fig. 3.1 and the Gibbs equation to determine:

  • ΔS\Delta S^\ominus, in J K1mol1\text{J K}^{-1} \text{mol}^{-1}, for reaction 2
  • the minimum temperature, TT, in K\text{K}, at which the reaction is feasible
  • ΔH\Delta H^\ominus, in kJ mol1\text{kJ mol}^{-1}, for reaction 2.
Similar questions
Q32024 May/Jun·P422 partsMedium
(a)

Carbon disulfide, CS2\text{CS}_2, is flammable and reacts readily with oxygen, as shown in reaction 1.

reaction 1CS2(g)+3O2(g)CO2(g)+2SO2(g)\text{reaction 1} \quad \text{CS}_2(\text{g}) + 3\text{O}_2(\text{g}) \rightarrow \text{CO}_2(\text{g}) + 2\text{SO}_2(\text{g})

Table 3.1 shows the standard enthalpy of formation, ΔHf\Delta H_{\text{f}}^{\ominus}, and the standard entropy, SS^{\ominus}, for some substances.

Table 3.1

CS2(g)\text{CS}_2(\text{g})O2(g)\text{O}_2(\text{g})CO2(g)\text{CO}_2(\text{g})SO2(g)\text{SO}_2(\text{g})
ΔHf/kJ mol1\Delta H_{\text{f}}^{\ominus} / \text{kJ mol}^{-1}116.70.0-393.5-296.8
S/J K1mol1S^{\ominus} / \text{J K}^{-1} \text{mol}^{-1}237.8205.2213.8248.2

Calculate the standard Gibbs free energy change, ΔG\Delta G^{\ominus}, in kJ mol1\text{kJ mol}^{-1}, for reaction 1 at 25 C25\text{ }^{\circ}\text{C}.

ΔG=.............................. kJ mol1\Delta G^{\ominus} = \text{..............................} \text{ kJ mol}^{-1}
(b)

Carbon disulfide reacts with chlorine to form tetrachloromethane, as shown in reaction 2.

reaction 2CS2+3Cl2CCl4+S2Cl2ΔH=261.6 kJ mol1, ΔS=365.5 J K1mol1\text{reaction 2} \quad \text{CS}_2 + 3\text{Cl}_2 \rightarrow \text{CCl}_4 + \text{S}_2\text{Cl}_2 \quad \Delta H^{\ominus} = -261.6 \text{ kJ mol}^{-1}, \ \Delta S^{\ominus} = -365.5 \text{ J K}^{-1} \text{mol}^{-1}

Calculate the maximum temperature, in K\text{K}, for reaction 2 to be feasible.

temperature=.............................. K\text{temperature} = \text{..............................} \text{ K}
Similar questions
Q22024 Oct/Nov·P419 partsMedium-Easy
(a)

Predict and explain the variation in enthalpy change of hydration for the ions F\text{F}^-, Cl\text{Cl}^-, Br\text{Br}^- and I\text{I}^-.

(b)(i)

Complete line D. Include state symbols.

(b)(ii)

The value of the enthalpy change for process 1 can be calculated using the values of five other enthalpy changes which are not referred to in Fig. 2.1.

process 1: Ca(s)+F2(g)Ca2+(g)+2F(g)\text{process 1: } \text{Ca(s)} + \text{F}_2\text{(g)} \rightarrow \text{Ca}^{2+}\text{(g)} + 2\text{F}^-\text{(g)}

Identify these five other enthalpy changes, using either names or symbols.

(b)(iii)

Define lattice energy, ΔHlatt\Delta H_{\text{latt}}.

(b)(iv)

Complete the expression to give the mathematical relationship between ΔHlatt\Delta H_{\text{latt}} of calcium fluoride and the enthalpy changes for processes 1 and 3.

ΔHlatt=\Delta H_{\text{latt}} =
(c)

Use data from Table 2.1 to calculate a value for the hydration energy, ΔHhyd\Delta H_{\text{hyd}}, of fluoride ions, F(g)\text{F}^-\text{(g)}.

Table 2.1

value / kJmol1\text{kJ}\,\text{mol}^{-1}
enthalpy change of solution of calcium fluoride, CaF2(s)\text{CaF}_2\text{(s)}+13+13
overall enthalpy change of process 1 in Fig. 2.1+1395+1395
enthalpy change of formation of calcium fluoride1214-1214
enthalpy change of hydration of Ca2+(g)\text{Ca}^{2+}\text{(g)}1650-1650
ΔHhyd  F(g)=..............................  kJmol1\Delta H_{\text{hyd}} \; \text{F}^-\text{(g)} = \text{..............................} \; \text{kJ}\,\text{mol}^{-1}
(d)

Define entropy.

(e)

At 298 K298\text{ K}, the Gibbs free energy change, ΔG\Delta G, for the solution of compound T\mathbf{T} is +6.00 kJmol1+6.00\text{ kJ}\,\text{mol}^{-1}.

The enthalpy change of solution, ΔHsol\Delta H_{\text{sol}}, of compound T\mathbf{T} is +30.0 kJmol1+30.0\text{ kJ}\,\text{mol}^{-1} at 298 K298\text{ K}.

Calculate the value of the entropy change, ΔS\Delta S, for the solution of compound T\mathbf{T} at 298 K298\text{ K}.

ΔS=..............................  JK1mol1\Delta S = \text{..............................} \; \text{J}\,\text{K}^{-1}\,\text{mol}^{-1}
(f)

Predict whether compound T\mathbf{T} becomes more or less soluble as the water is heated from 298 K298\text{ K} to 360 K360\text{ K}. Explain your answer.

Similar questions
Q22024 Oct/Nov·P428 partsMedium-Easy
(a)

Predict and explain the variation in enthalpy change of hydration for the ions Na+\text{Na}^+, Mg2+\text{Mg}^{2+} and Al3+\text{Al}^{3+}.

(b)(i)

Complete line C on Fig. 2.1. Include state symbols.

(b)(ii)

Use both words and symbols to identify change 2 on Fig. 2.1.

Use changes 1 and 3 as examples of how this should be done.

(b)(iii)

Calculate a value for the lattice energy of magnesium chloride, ΔHlatt MgCl2(s)\Delta H_{\text{latt}}\text{ MgCl}_2(\text{s}), by selecting and using appropriate data from Table 2.1.

Table 2.1

energy changevalue / kJ mol1\text{kJ mol}^{-1}
enthalpy change of solution of magnesium chloride155-155
enthalpy change of formation of magnesium chloride642-642
first ionisation energy of magnesium+736+736
second ionisation energy of magnesium+1450+1450
electron affinity of chlorine349-349
enthalpy change of hydration of Mg2+\text{Mg}^{2+}1920-1920
enthalpy change of hydration of Cl\text{Cl}^-364-364
ΔHlatt MgCl2(s)=.............................. kJ mol1\Delta H_{\text{latt}}\text{ MgCl}_2(\text{s}) = \text{.............................. kJ mol}^{-1}
(c)

Define entropy.

(d)

At 25C25^\circ\text{C} the enthalpy change of solution of compound Z\mathbf{Z} is +26 kJ mol1+26\text{ kJ mol}^{-1}. The entropy change of solution of Z\mathbf{Z} at the same temperature is +52 J K1mol1+52\text{ J K}^{-1}\text{mol}^{-1}.

Calculate the value of the Gibbs free energy change, ΔG\Delta G, for the solution of Z\mathbf{Z} at 25C25^\circ\text{C}.

ΔG=.............................. kJ mol1\Delta G = \text{.............................. kJ mol}^{-1}
(e)(i)

Use your answer to (d) to predict whether or not Z\mathbf{Z} is soluble in water at 25C25^\circ\text{C}. Explain your answer.

(e)(ii)

Predict whether Z\mathbf{Z} becomes more or less soluble as the water is heated from 25C25^\circ\text{C} to 95C95^\circ\text{C}. Explain your answer.

Similar questions
Q22024 Oct/Nov·P439 partsMedium-Easy
(a)

Predict and explain the variation in enthalpy change of hydration for the ions F\text{F}^-, Cl\text{Cl}^-, Br\text{Br}^- and I\text{I}^-.

(b)(i)

Complete line D. Include state symbols.

(b)(ii)

The value of the enthalpy change for process 1 can be calculated using the values of five other enthalpy changes which are not referred to in Fig. 2.1.

process 1: Ca(s)+F2(g)Ca2+(g)+2F(g)\text{process 1: } \text{Ca(s)} + \text{F}_2\text{(g)} \rightarrow \text{Ca}^{2+}\text{(g)} + 2\text{F}^-\text{(g)}

Identify these five other enthalpy changes, using either names or symbols.

(b)(iii)

Define lattice energy, ΔHlatt\Delta H_{\text{latt}}.

(b)(iv)

Complete the expression to give the mathematical relationship between ΔHlatt\Delta H_{\text{latt}} of calcium fluoride and the enthalpy changes for processes 1 and 3.

ΔHlatt=................................................................................\Delta H_{\text{latt}} = \text{................................................................................}
(c)

Use data from Table 2.1 to calculate a value for the hydration energy, ΔHhyd\Delta H_{\text{hyd}}, of fluoride ions, F(g)\text{F}^-\text{(g)}.

Table 2.1

value / kJ mol1\text{kJ mol}^{-1}
enthalpy change of solution of calcium fluoride, CaF2(s)\text{CaF}_2\text{(s)}+13
overall enthalpy change of process 1 in Fig. 2.1+1395
enthalpy change of formation of calcium fluoride-1214
enthalpy change of hydration of Ca2+(g)\text{Ca}^{2+}\text{(g)}-1650
ΔHhyd F(g)=.............................. kJ mol1\Delta H_{\text{hyd}} \text{ F}^-\text{(g)} = \text{.............................. kJ mol}^{-1}
(d)

Define entropy.

(e)

At 298 K298\text{ K}, the Gibbs free energy change, ΔG\Delta G, for the solution of compound T is +6.00 kJ mol1+6.00\text{ kJ mol}^{-1}.

The enthalpy change of solution, ΔHsol\Delta H_{\text{sol}}, of compound T is +30.0 kJ mol1+30.0\text{ kJ mol}^{-1} at 298 K298\text{ K}.

Calculate the value of the entropy change, ΔS\Delta S, for the solution of compound T at 298 K298\text{ K}.

ΔS=.............................. J K1 mol1\Delta S = \text{.............................. J K}^{-1}\text{ mol}^{-1}
(f)

Predict whether compound T becomes more or less soluble as the water is heated from 298 K298\text{ K} to 360 K360\text{ K}. Explain your answer.

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